| Date | May 2016 | Marks available | 4 | Reference code | 16M.1.hl.TZ1.2 |
| Level | HL only | Paper | 1 | Time zone | TZ1 |
| Command term | Find | Question number | 2 | Adapted from | N/A |
Question
At a skiing competition the mean time of the first three skiers is 34.1 seconds. The time for the fourth skier is then recorded and the mean time of the first four skiers is 35.0 seconds. Find the time achieved by the fourth skier.
Markscheme
total time of first 3 skiers \( = 34.1 \times 3 = 102.3\) (M1)A1
total time of first 4 skiers \( = 35.0 \times 4 = 140.0\) A1
time taken by fourth skier \( = 140.0 - 102.3 = 37.7{\text{ (seconds)}}\) A1
[4 marks]
Examiners report
This was done successfully by almost all candidates.
