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Date May 2013 Marks available 1 Reference code 13M.2.HL.TZ2.2
Level Higher level Paper Paper 2 Time zone Time zone 2
Command term Determine Question number 2 Adapted from N/A

Question

The image shows the karyotype of a person who developed as a female.

In a strain of soybeans, high oil content (H) in seeds is dominant to low oil content (h)  and four seeds in a pod (F) is dominant to two seeds in a pod (f).  A farmer crosses  two soybean plants, both with high oil content and four seeds in a pod.  The offspring have a phenotypic ratio of 9 : 3 : 3 : 1.

Identify the genotypes of the soybean plants with high oil content and four seeds in a pod that were used in the cross.

[1]
a (i).

In a strain of soybeans, high oil content (H) in seeds is dominant to low oil content (h)  and four seeds in a pod (F) is dominant to two seeds in a pod (f).  A farmer crosses  two soybean plants, both with high oil content and four seeds in a pod.  The offspring have a phenotypic ratio of 9 : 3 : 3 : 1.

Determine the genotypes of the gametes and offspring using a Punnett grid.

 

[2]
a (ii).

In a strain of soybeans, high oil content (H) in seeds is dominant to low oil content (h)  and four seeds in a pod (F) is dominant to two seeds in a pod (f).  A farmer crosses  two soybean plants, both with high oil content and four seeds in a pod.  The offspring have a phenotypic ratio of 9 : 3 : 3 : 1.

Identify the phenotypes of each part of the phenotypic ratio.

 

[2]
a (iii).

Deduce the reason for the person developing as a female.

[1]
b (i).

Determine, with a reason, whether this karyotype shows that non-disjunction has occurred.

[1]
b (ii).

Markscheme

 HhFf HhFf  / (both) HhFf;

a (i).

all gametes shown correctly on Punnett grid;
all offspring genotypes correct;

a (ii).

 Award [1] for any two correct phenotypes.

a (iii).

no Y chromosome.

b (i).

yes as there is only one X chromosome/chromosome missing/only 45 chromosomes

b (ii).

Examiners report

Most wrote the correct genotype, though there were a surprising number that did not follow notation conventions such as writing HFhf or using linkage notation. 

a (i).

The majority of students could answer this question. Where students were not answering correctly, it was due to a lack of conceptual understanding of segregation; i.e. writing gametes as HH or ff for example.

a (ii).

This question was most commonly answered correctly.

a (iii).

Approximately half of students answered this correctly.   A number did not recognize the condition for determining a female was the absence of the Y chromosome rather than the presence of the X chromosome.

b (i).

This was more commonly answered correctly than i).  Here a common misunderstanding was that nondisjunction could only be present if additional chromosomes were present rather than if one were missing.

b (ii).

Syllabus sections

Additional higher level » Topic 10: Genetics and evolution » 10.2 Inheritance
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