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Date None Specimen Marks available 3 Reference code SPNone.1.hl.TZ0.10
Level HL only Paper 1 Time zone TZ0
Command term Calculate and Estimate Question number 10 Adapted from N/A

Question

Bill is investigating whether or not there is a positive association between the heights and weights of boys of a certain age. He defines the hypotheses\[{{\rm{H}}_0}:\rho  = 0;{{\rm{H}}_1}:\rho  > 0 ,\]where \(\rho \) denotes the population correlation coefficient between heights and weights of boys of this age. He measures the height, \(h\) cm, and weight, \(w\) kg, of each of a random sample of \(20\) boys of this age and he calculates the following statistics.\[\sum {w = 340,\sum {h = 2002,\sum {{w^2} = 5830} } } ,\sum {{h^2} = 201124} ,\sum {hw = 34150} \]

(i)     Calculate the correlation coefficient for this sample.

(ii)     Calculate the \(p\)-value of your result and interpret it at the \(1\% \) level of significance.

[8]
a.

(i)     Calculate the equation of the least squares regression line of \(w\) on \(h\) .

(ii)     The height of a randomly selected boy of this age of \(90\) cm. Estimate his weight.

[3]
b.

Markscheme

(i)     \(r = \frac{{34150 - 340 \times \frac{{2002}}{{20}}}}{{\sqrt {\left( {5830 - \frac{{{{340}^2}}}{{20}}} \right)} \left( {201124 - \frac{{{{2002}^2}}}{{20}}} \right)}}\)     (M1)(A1)

Note: Accept equivalent formula.

 

\( = 0.610\)     A1

 

(ii)     (\(T = R \times \sqrt {\frac{{n - 2}}{{1 - {R^2}}}} \) has the t-distribution with \(n - 2\) degrees of freedom)

\(t = 0.6097666 \ldots \sqrt {\frac{{18}}{{1 - 0.6097666{ \ldots ^2}}}} \)     M1

\( = 3.2640 \ldots \)     A1

\({\rm{DF}} = 18\)     A1

\(p{\rm{ - value}} = 0.00215 \ldots \)     A1

this is less than \(0.01\), so we conclude that there is a positive association between heights and weights of boys of this age     R1

 

[8 marks]

a.

(i)     the equation of the regression line of \(w\) on \(h\) is

\(w - \frac{{340}}{{20}} = \left( {\frac{{20 \times 34150 - 340 \times 2002}}{{20 \times 201124 - {{2002}^2}}}} \right)\left( {h - \frac{{2002}}{{20}}} \right)\)     M1

\(w = 0.160h + 0.957\)     A1

 

(ii) putting \(h = 90\) , \(w = 15.4\) (kg)     A1

Note: Award M0A0A0 for calculation of \(h\) on \(w\).

 

[3 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 3 - Statistics and probability » 3.7 » Introduction to bivariate distributions.

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