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Date May 2018 Marks available 5 Reference code 18M.1.hl.TZ0.3
Level HL only Paper 1 Time zone TZ0
Command term Find Question number 3 Adapted from N/A

Question

A number written in base 5 is 4303. Find this as a number written in base 10.

[2]
a.

1000 is a number written in base 10. Find this as a number written in base 7.

[5]
b.

Markscheme

43035 = 4 × 53 + 3 × 52 + 0 × 51 + 3 × 50        (M1)
= 500 + 75 + 3
= 578        A1

[2 marks]

a.

METHOD 1

1000=a0+7a1+49a2+343a3      (M1)

(since 343a3<1000)a3=2     (A1)

1000=a0+7a1+49a2+686

a0+7a1+49a2=314a2=6     (A1)

a0+7a1=20a1=2,a0=6     (A1)

100010=26267      A1

 

METHOD 2

1000 = 7 × 142 + 6      (M1)

142 = 7 × 20 + 2     (A1)

20 = 7 × 2 + 6     (A1)

2 = 7 × 0 + 2     (A1)

⇒ (1000)10 = 26267      A1

[5 marks]

 

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 6 - Discrete mathematics » 6.5 » Representation of integers in different bases.

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