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Date May 2011 Marks available 2 Reference code 11M.1.sl.TZ2.12
Level SL only Paper 1 Time zone TZ2
Command term Find Question number 12 Adapted from N/A

Question

A manufacturer in England makes \(16 000\) garden statues. \(12\% \) are defective and cannot be sold.

Find the number of statues that are non-defective.

[2]
a.

The manufacturer sells each non-defective statue for \(5.25\) British pounds (GBP) to an American company. The exchange rate from GBP to US dollars (USD) is \(1{\text{ GBP}} = 1.6407{\text{ USD}}\).

Calculate the amount in USD paid by the American company for all the non-defective statues. Give your answer correct to two decimal places.

[2]
b.

The American company sells one of the statues to an Australian customer for \(12{\text{ USD}}\). The exchange rate from Australian dollars (AUD) to USD is \(1{\text{ AUD}} = 0.8739{\text{ USD}}\) .

Calculate the amount that the Australian customer pays, in AUD, for this statue. Give your answer correct to two decimal places.

[2]
c.

Markscheme

\(0.88 \times 16000\)     OR     \(16000 - 0.12 \times 16000\)     (M1)

\(14080\)     (A1)     (C2)

[2 marks]

a.

\(1.6407 \times 5.25 \times 14080\)     (M1)

\(121 280.54{\text{ USD}}\)     (A1)(ft)     (C2)

Note: Follow through from their answer to part (a).

[2 marks]

b.

\(12 \times \frac{1}{{0.8739}}\)     (M1)

\(13.73{\text{ AUD}}\)     (A1)     (C2)

Note: If division used in part (b) and multiplication used in part (c), award (M0)(A0) for part (b) and (M1)(A1)(ft) for part (c).

[2 marks]

c.

Examiners report

This question was generally well answered with much correct working seen in parts (a) and (b). The most popular incorrect answer in part (a) was \(1920\) – candidates simply stating the number of defective items rather than the number of non-defective items. Unfortunately in part (c) many candidates multiplied by \(0.8739\) rather than divided and \(10.49\) proved a popular, but erroneous, answer.

a.

This question was generally well answered with much correct working seen in parts (a) and (b). The most popular incorrect answer in part (a) was \(1920\) – candidates simply stating the number of defective items rather than the number of non-defective items. Unfortunately in part (c) many candidates multiplied by \(0.8739\) rather than divided and \(10.49\) proved a popular, but erroneous, answer.

b.

This question was generally well answered with much correct working seen in parts (a) and (b). The most popular incorrect answer in part (a) was \(1920\) – candidates simply stating the number of defective items rather than the number of non-defective items. Unfortunately in part (c) many candidates multiplied by \(0.8739\) rather than divided and \(10.49\) proved a popular, but erroneous, answer.

c.

Syllabus sections

Topic 1 - Number and algebra » 1.0 » Simple applications of ratio, percentage and proportion.

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