Date | November 2015 | Marks available | 6 | Reference code | 15N.1.sl.TZ0.3 |
Level | SL only | Paper | 1 | Time zone | TZ0 |
Command term | Find | Question number | 3 | Adapted from | N/A |
Question
Let f′(x)=6x2−5. Given that f(2)=−3, find f(x).
Markscheme
evidence of antidifferentiation (M1)
egf=∫f′
correct integration (accept absence of C) (A1)(A1)
f(x)=6x33−5x+C, 2x3−5x
attempt to substitute (2, −3) into their integrated expression (must have C) M1
eg2(2)3−5(2)+C=−3, 16−10+C=−3
Note: Award M0 if substituted into original or differentiated function.
correct working to find C (A1)
eg16−10+C=−3, 6+C=−3, C=−9
f(x)=2x3−5x−9 A1 N4
[6 marks]
Examiners report
[N/A]