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Date November 2015 Marks available 6 Reference code 15N.1.sl.TZ0.3
Level SL only Paper 1 Time zone TZ0
Command term Find Question number 3 Adapted from N/A

Question

Let f(x)=6x25. Given that f(2)=3, find f(x).

Markscheme

evidence of antidifferentiation     (M1)

egf=f

correct integration (accept absence of C)     (A1)(A1)

f(x)=6x335x+C, 2x35x

attempt to substitute (2, 3) into their integrated expression (must have C)     M1

eg2(2)35(2)+C=3, 1610+C=3

 

Note:     Award M0 if substituted into original or differentiated function.

 

correct working to find C     (A1)

eg1610+C=3, 6+C=3, C=9

f(x)=2x35x9     A1     N4

[6 marks]

Examiners report

[N/A]

Syllabus sections

Topic 6 - Calculus » 6.5 » Anti-differentiation with a boundary condition to determine the constant term.

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