Date | May 2021 | Marks available | 1 | Reference code | 21M.1.SL.TZ2.14 |
Level | Standard level | Paper | Paper 1 | Time zone | 2 |
Command term | Question number | 14 | Adapted from | N/A |
Question
Unpolarized light of intensity is incident on a polarizer. The light that passes through this polarizer then passes through a second polarizer.
The second polarizer can be rotated to vary the intensity of the emergent light. What is the maximum value of the intensity emerging from the second polarizer?
A.
B.
C.
D.
Markscheme
B
Examiners report
Syllabus sections
- 17N.1.SL.TZ0.14: Two wave pulses, each of amplitude A, approach each other. They then superpose...
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22M.1.SL.TZ2.18:
Unpolarized light with an intensity of 320 W m−2 goes through a polarizer and an analyser, originally aligned parallel.
The analyser is rotated through an angle θ = 30°. Cos 30° = .
What is the intensity of the light emerging from the analyser?
A. 120 W m−2
B. W m−2
C. 240 W m−2
D. W m−2
- 22M.2.SL.TZ1.3b: State and explain the wavelength of the sound measured at M.
- 17M.2.SL.TZ1.2a: Outline what is meant by the principle of superposition of waves.
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16N.1.HL.TZ0.14:
A point source of light of amplitude A0 gives rise to a particular light intensity when viewed at a distance from the source. When the amplitude is increased and the viewing distance is doubled, the light intensity is doubled. What is the new amplitude of the source?
A. 2A0
B. 2 A0
C. 4A0
D. 8A0
- 17M.1.SL.TZ1.15: Two pulses are travelling towards each other. What is a possible pulse shape when the...
- 17M.1.SL.TZ2.16: A beam of unpolarized light is incident on the first of two parallel polarizers. The...
- 18N.1.HL.TZ0.14: X and Y are two coherent sources of waves. The phase difference between X and Y is zero. The...
- 19N.1.SL.TZ0.15: Unpolarized light is incident on two polarizing filters X and Y. They are arranged so that...
- 19M.2.SL.TZ1.3a: Explain why intensity maxima are observed at X and Y.
- 19M.1.SL.TZ2.15: Unpolarized light is incident on two polarizers. The axes of polarization of both polarizers...
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21N.1.SL.TZ0.15:
Horizontally polarized light is incident on a pair of polarizers X and Y. The axis of polarization of X makes an angle θ with the horizontal. The axis of polarization of Y is vertical.
What is θ so that the intensity of the light transmitted through Y is a maximum?
A.B.
C.
D.
- 17M.1.HL.TZ1.13: Properties of waves are I. polarizationII. diffractionIII. refraction Which of these...
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16N.2.SL.TZ0.5b:
Radio waves are emitted by a straight conducting rod antenna (aerial). The plane of polarization of these waves is parallel to the transmitting antenna.
An identical antenna is used for reception. Suggest why the receiving antenna needs to be be parallel to the transmitting antenna.
- 21N.2.SL.TZ0.3b.ii: Identify a time at which the displacement of P is zero.
- 21N.2.HL.TZ0.2c.ii: Identify a time at which the displacement of P is zero.
- 21N.2.HL.TZ0.2c.iii: Estimate the amplitude of the resultant wave.
- 19M.2.HL.TZ1.3a: Explain why intensity maxima are observed at X and Y.
- 19M.2.HL.TZ1.3c: Outline one reason why the maxima observed at W, X and Y will have different intensities from...
- 19M.1.SL.TZ2.30: The orbital radius of the Earth around the Sun is 1.5 times that of Venus. What is the...
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17M.1.SL.TZ1.16:
Unpolarized light of intensity I0 is incident on the first of two polarizing sheets. Initially the planes of polarization of the sheets are perpendicular.
Which sheet must be rotated and by what angle so that light of intensity can emerge from the second sheet?
- 22M.2.SL.TZ2.3b: The metal plate is replaced by a wooden plate that reflects a lower intensity sound wave than...
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19M.2.HL.TZ2.3eii:
Calculate the wavelength measured by the observer.
- 22M.2.HL.TZ1.3b: State and explain the wavelength of the sound measured at M.
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18N.2.HL.TZ0.8c.i:
Show that the intensity of solar radiation at the orbit of Mars is about 600 W m–2.
- 21M.1.SL.TZ1.15: Two identical waves, each with amplitude X0 and intensity I, interfere constructively. What...
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20N.2.SL.TZ0.4c:
When both loudspeakers are operating, the intensity of sound recorded at Q is . Loudspeaker B is now disconnected. Loudspeaker A continues to emit sound with unchanged amplitude and frequency. The intensity of sound recorded at Q changes to .
Estimate .
- 21M.1.HL.TZ2.12: Which graph shows the variation of amplitude with intensity for a wave?
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20N.2.HL.TZ0.4c:
When both loudspeakers are operating, the intensity of sound recorded at Q is . Loudspeaker B is now disconnected. Loudspeaker A continues to emit sound with unchanged amplitude and frequency. The intensity of sound recorded at Q changes to .
Estimate .
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18N.2.SL.TZ0.6a:
Show that the intensity of solar radiation at the orbit of Mars is about 600 W m–2.
- 19M.2.SL.TZ1.3c: Outline one reason why the maxima observed at W, X and Y will have different intensities from...
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21M.1.SL.TZ2.15:
Two wave generators, placed at position P and position Q, produce water waves with a wavelength of. Each generator, operating alone, will produce a wave oscillating with an amplitude of at position R. PR is and RQ is .
Both wave generators now operate together in phase. What is the amplitude of the resulting wave at R?
A.B.
C.
D. zero
- 19M.1.SL.TZ1.17: Which of these waves cannot be polarized? A. microwaves B. ultrasound C. ultraviolet D. X...
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19M.2.HL.TZ1.3d:
The microwaves emitted by the transmitter are horizontally polarized. The microwave receiver contains a polarizing filter. When the receiver is at position W it detects a maximum intensity.
The receiver is then rotated through 180° about the horizontal dotted line passing through the microwave transmitter. Sketch a graph on the axes provided to show the variation of received intensity with rotation angle.
- 21N.2.SL.TZ0.3b.iii: Estimate the amplitude of the resultant wave.
-
21N.2.SL.TZ0.6a.i:
Show that the intensity of the solar radiation at the location of Titan is 16 W m−2
-
21N.2.HL.TZ0.6a.i:
Show that the intensity of the solar radiation at the location of Titan is 16 W m−2.
-
22M.1.SL.TZ1.14:
A light source of power P is observed from a distance . The power of the source is then halved.
At what distance from the source will the intensity be the same as before?
A.
B.
C.
D.
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22M.1.SL.TZ1.16:
A beam of unpolarized light of intensity is incident on a polarizing filter. The polarizing filter is rotated through an angle θ. What is the variation in the intensity of the beam with angle θ after passing through the polarizing filter?
-
22M.2.SL.TZ1.3a:
Explain why the received intensity varies between maximum and minimum values.
-
22M.2.SL.TZ1.3c:
B is placed at the first minimum. The frequency is then changed until the received intensity is again at a maximum.
Show that the lowest frequency at which the intensity maximum can occur is about 3 kHz.
Speed of sound = 340 m s−1
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22M.2.HL.TZ1.3a:
Explain why the received intensity varies between maximum and minimum values.
-
22M.2.HL.TZ1.3c:
B is placed at the first minimum. The frequency is then changed until the received intensity is again at a maximum.
Show that the lowest frequency at which the intensity maximum can occur is about 3 kHz.
Speed of sound = 340 m s−1
- 22M.2.SL.TZ2.3a.i: Explain the variation in intensity.