Date | May 2021 | Marks available | 2 | Reference code | 21M.2.SL.TZ1.4 |
Level | Standard level | Paper | Paper 2 | Time zone | 1 |
Command term | Explain | Question number | 4 | Adapted from | N/A |
Question
A planet orbits at a distance d from a star. The power emitted by the star is P. The total surface area of the planet is A.
Explain why the power incident on the planet is
The albedo of the planet is . The equilibrium surface temperature of the planet is T. Derive the expression
where e is the emissivity of the planet.
On average, the Moon is the same distance from the Sun as the Earth. The Moon can be assumed to have an emissivity e = 1 and an albedo = 0.13. The solar constant is 1.36 × 103 W m−2. Calculate the surface temperature of the Moon.
Markscheme
is the power received by the planet/at a distance d «from star» ✓
is the projected area/cross sectional area of the planet ✓
use of ✓
with correct manipulation to show the result ✓
✓
T = 268.75 «K» ≅ 270 «K» ✓