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Date November 2019 Marks available 2 Reference code 19N.2.SL.TZ0.4
Level Standard level Paper Paper 2 Time zone 0 - no time zone
Command term Explain Question number 4 Adapted from N/A

Question

A proton is moving in a region of uniform magnetic field. The magnetic field is directed into the plane of the paper. The arrow shows the velocity of the proton at one instant and the dotted circle gives the path followed by the proton.

The speed of the proton is 2.0 × 106 m s–1 and the magnetic field strength B is 0.35 T.

Explain why the path of the proton is a circle.

[2]
a.

Show that the radius of the path is about 6 cm.

[2]
b(i).

Calculate the time for one complete revolution.

[2]
b(ii).

Explain why the kinetic energy of the proton is constant.

[2]
c.

Markscheme

magnetic force is to the left «at the instant shown»
OR
explains a rule to determine the direction of the magnetic force ✔

force is perpendicular to velocity/«direction of» motion
OR
force is constant in magnitude ✔

force is centripetal/towards the centre ✔

NOTE: Accept reference to acceleration instead of force

a.

qvB=mv2R

R=1.67×10-27×2.0×1061.6×10-19×0.35 OR 0.060 « m »

NOTE: Award MP2 for full replacement or correct answer to at least 2 significant figures

b(i).

T=2πRv

T=«2π×0.062.0×106=1.9×10-7 « s » ✔

NOTE: Award [2] for bald correct answer

b(ii).

ALTERNATIVE 1
work done by force is change in kinetic energy ✔
work done is zero/force perpendicular to velocity ✔

NOTE: Award [2] for a reference to work done is zero hence Ek remains constant

 

ALTERNATIVE 2
proton moves at constant speed ✔
kinetic energy depends on speed ✔

NOTE: Accept mention of speed or velocity indistinctly in MP2

 

c.

Examiners report

[N/A]
a.
[N/A]
b(i).
[N/A]
b(ii).
[N/A]
c.

Syllabus sections

Core » Topic 6: Circular motion and gravitation » 6.1 – Circular motion
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Core » Topic 6: Circular motion and gravitation
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