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Date November 2017 Marks available 2 Reference code 17N.2.sl.TZ0.4
Level SL Paper 2 Time zone TZ0
Command term Calculate Question number 4 Adapted from N/A

Question

Menthol is an organic compound containing carbon, hydrogen and oxygen.

Complete combustion of 0.1595 g of menthol produces 0.4490 g of carbon dioxide and 0.1840 g of water. Determine the empirical formula of the compound showing your working.

[3]
a.

0.150 g sample of menthol, when vaporized, had a volume of 0.0337 dm3 at 150 °C and 100.2 kPa. Calculate its molar mass showing your working.

[2]
b.

Markscheme

carbon: « 0.4490 g 44.01 g mo l 1 » = 0.01020 «mol» / 0.1225 «g»

OR

hydrogen: « 0.1840 × 2 18.02 » = 0.02042 «mol» / 0.0206 «g»

oxygen: «0.1595 – (0.1225 + 0.0206)» = 0.0164 «g» / 0.001025 «mol»

empirical formula: C10H20O

Award [3] for correct final answer.

a.

temperature = 423 K

OR

«M = m R T p V

« = 0.150 g × 8.31 J  K 1 mol 1 × 423 K 100.2 kPa × 0.0337 d m 3 = » 156 «g mol–1»

Award [1] for correct answer with no working shown.

Accept “pV = nRT AND n =  m M ” for M1.

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Core » Topic 1: Stoichiometric relationships » 1.3 Reacting masses and volumes
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Core » Topic 1: Stoichiometric relationships
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