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Date November 2017 Marks available 1 Reference code 17N.1.hl.TZ0.4
Level HL Paper 1 Time zone TZ0
Command term Question number 4 Adapted from N/A

Question

A compound with Mr = 102 contains 58.8 % carbon, 9.80 % hydrogen and 31 % oxygen by mass.
What is its molecular formula?

Ar: C = 12.0; H = 1.0; O = 16.0

A. C2H14O4

B. C3H4O4

C. C5H10O2

D. C6H14O

Markscheme

C

Examiners report

[N/A]

Syllabus sections

Core » Topic 1: Stoichiometric relationships » 1.2 The mole concept
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