Date | November 2017 | Marks available | 2 | Reference code | 17N.2.HL.TZ0.05 |
Level | Higher level | Paper | Paper 2 | Time zone | TZ0 / no time zone |
Command term | Describe | Question number | 05 | Adapted from | N/A |
Question
Describe the process of crossing over.
Explain the reason for linked genes not following the pattern of inheritance discovered by Mendel.
Markscheme
a. occurs during prophase I/during meiosis
b. homologous chromosomes form bivalents/pair up
c. breakage and rejoining of chromatids
d. exchange «of DNA/alleles» between non-sister chromatids/homologous chromosomes
[Max 2 Marks]
a. «linked genes are» on the same chromosome
b. Mendel's genes were on different chromosomes
c. linked genes are inherited together
OR
no independent assortment
d. «linked genes» only separated by crossing over
OR
fewer recombinants than with unlinked genes
Reject sex-linkage
Examiners report
Syllabus sections
- 22M.1.HL.TZ1.36: An individual is heterozygous for two linked genes . To investigate the frequency of...
- 17M.2.HL.TZ2.7a: Outline how reproductive isolation can occur in an animal population.
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22M.2.HL.TZ2.3b:
To calculate chi-squared, expected values must first be calculated. Assuming that there is no association between the two species, calculate the expected number of quadrats in which both species would be present, showing your working.
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22M.2.HL.TZ2.3c:
State the number of degrees of freedom for this test to determine the critical value of chi-squared.
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18M.1.HL.TZ1.36:
What could account for this distribution of height in a population?
[Source: Graph adapted from Six Minutes http://sixminutes.dlugan.com/good-public-speaker-average/]
A. Gene linkage
B. Dominant alleles
C. Independent assortment
D. Multiple genes
- 20N.1.HL.TZ0.35: Andalusian fowl have varied colours and types of feathers. The allele for black feathers is...
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21M.2.HL.TZ2.5a:
Autosomal genes are located in chromosomes that are not sex chromosomes. The inheritance of autosomal genes is affected by whether the genes are linked or unlinked. Explain the two types of inheritance, using the example of parents that are heterozygous for two genes A and B.
- 19N.2.HL.TZ0.2b: Identify the recombinants.
- 17N.1.HL.TZ0.35: How do the concepts of gradualism and punctuated equilibrium differ? A. The timing of...
- 17M.1.HL.TZ2.20: The graph shows variations in beak size for the bird Geospiza fortis on an island in the...
- 17M.2.HL.TZ2.8b: Draw a labelled diagram of the formation of a chiasma by crossing over.
- 16N.1.SL.TZ0.16: The diagram shows a pedigree chart. What does it reveal about the inheritance of the blood...
- 20N.1.HL.TZ0.36: Many commercially produced bananas are triploid instead of diploid. The nucleus of a triploid...
- 21M.1.HL.TZ1.35: Which statement is valid regarding chromatids? A. Sister chromatids separate during meiosis...
- 17M.1.HL.TZ1.36: What can lead to reproductive isolation after just one generation? A. Polyploidy B....
- 17M.1.HL.TZ1.35: Which gametes can result from the following crossover?
- 16N.2.HL.TZ0.4a: List two causes of variation within a gene pool.
- 21N.2.HL.TZ0.2b.ii: State the stage of meiosis where chiasmata formation may occur.
- 18M.1.HL.TZ1.10: What is always passed to the next generation as a result of sexual reproduction? A....
- 18M.1.HL.TZ2.21: Which example shows disruptive selection? A. Giraffe necks have become longer over time. B....
- 18N.1.HL.TZ0.36: The image shows variation in height of adult humans. What can explain the variation? A. ...
- 18M.2.HL.TZ2.3a.i: The micrograph shows a plant cell of Lilium grandiflorum during meiosis. Identify, giving...
- 19M.1.HL.TZ1.35: Natural selection can operate in different ways. What is the effect of disruptive...
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19M.1.HL.TZ2.20:
William Bateson and Reginald Punnett used the sweet pea (Lathyrus odoratus) in genetics studies in the early 20th century. Pure-breeding plants that produced purple flowers and long pollen grains were crossed with pure-breeding plants that produced red flowers and round pollen grains. The resulting offspring all produced purple flowers and long pollen grains. Two of the F1 generation plants were crossed. The table shows the ratio of phenotypes in the F2 generation.
What is an explanation for these experimental results?
A. Purple flowers and long pollen grains are dominant and the alleles have assorted independently.
B. The genes for flower colour and pollen shape are linked and all plants producing long pollen grains are recombinants.
C. The genes for flower colour and pollen shape are linked and all plants producing red flowers are recombinants.
D. Plants producing purple flowers and round pollen grains arose through crossing over.
- 19N.1.HL.TZ0.36: A hunter tends to kill the bigger individuals of a population for their meat or for large...
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19M.1.HL.TZ2.19:
The cheetah (Acinonyx jubatus) is a large cat found in Africa. It has been discovered that organs could be transferred between any two individuals without rejection of the organ.
What is the probable reason for this?
A. Cheetahs have poor reproductive success.
B. Cheetahs have high heterozygosity.
C. Cheetahs have a large gene pool.
D. Cheetahs have a small gene pool.
- 17M.1.SL.TZ1.1: Which structure found in eukaryotes has a single membrane? A. Nucleus B. Lysosome C....
- 22M.1.HL.TZ1.35: What is polyploidy? A. Having an extra set of chromosomes B. Having an extra sex...
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22M.2.HL.TZ1.8c:
Explain the reasons for variation in human height.
- 16N.2.HL.TZ0.4c: Outline what is required for speciation to occur.
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21N.1.HL.TZ1.36:
The graph shows the relationship between mass at birth and the percentage that die shortly after birth for Scottish Blackface lambs.
[Source: Dwyer, C.M., Conington, J., Corbiere, F., Holmoy, I.H., Muri, K., Nowak, R., Rooke, J., Vipond, J. and Gautier,
J.-M., 2016. Invited review: Improving neonatal survival in small ruminants: science into practice. Animal, 10(3),
pp. 449–459.]What type of selection for the lambs is shown in the graph?
A. Disruptive selection, as there is a drop in mortality at intermediate birth masses
B. Stabilizing selection, as lambs with low or high birth mass are less likely to survive
C. Directional selection, as lambs with a high birth mass have high mortality
D. There is no evidence in the graph of selection, as survival frequency is not shown
- 19N.1.HL.TZ0.35: Which event happens in meiosis II but not in meiosis I? A. Spindle microtubules attach to...
- 21M.1.HL.TZ2.35: What process occurs in both mitosis and meiosis? A. Formation of chiasmata B. Reduction...
- 18M.1.HL.TZ1.35: What forms when two different chromatids of the same homologous pair cross over? A. Daughter...
- 16N.1.HL.TZ0.35: Some of the ratios that Morgan investigated in genetic crosses did not correspond with...
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22M.1.HL.TZ2.35:
When a cell divides by meiosis, chiasmata can be observed. Which are features of chiasmata?
I. They are points of attachment between chromatids of non-homologous chromosomes.
II. They occur during meiosis I.
III. They increase stability of bivalents.
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
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22M.2.HL.TZ2.7c:
Explain how speciation occurs, including the different processes of isolation and selection.
- 17N.2.HL.TZ0.05b: Explain the reason for linked genes not following the pattern of inheritance discovered by...
- 16N.1.HL.TZ0.36: Fossil records show that black bears increased in size during the Ice Age and decreased in...
- 21N.2.HL.TZ0.2b.i: Draw the same chromosomes to show their structure at the same stage of meiosis if there had...
- 19N.2.HL.TZ0.2c: The chi-squared value was calculated as shown. Deduce, with reasons, whether the observed...
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21M.1.HL.TZ1.36:
In fruit flies (Drosophila melanogaster), grey bodies (b+) are dominant to black bodies (b) and normal wings (vg+) are dominant to vestigial wings (vg). Homozygous vestigial winged, black bodied flies were crossed with individuals that were heterozygous for both traits. 2300 individuals were counted and the phenotypes observed were recorded as shown.
965 normal wings, grey bodies
944 vestigial wings, black bodies
206 vestigial wings, grey bodies
185 normal wings, black bodiesWhich statement is valid?
A. The predicted phenotypic ratio was 9:3:3: 1.
B. There is independent assortment of wings but not body colour.
C. The expected number of vestigial winged, grey bodied flies was 575.
D. The traits are on different chromosomes.
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21N.2.HL.TZ0.2c:
Explain gene linkage and its effects on inheritance.
- 21N.1.HL.TZ1.35: A dihybrid cross was carried out between two plants to determine whether the genes for seed...
- 18N.2.HL.TZ0.8c: Research suggests that many living plant species are polyploid. Explain how polyploidy occurs...
- 19M.2.HL.TZ1.2d.i: A fly that is homozygous dominant for both body colour and wing size mates with a fly that is...
- 18M.2.HL.TZ2.3a.ii: Outline the law of independent assortment.
- 21N.2.HL.TZ0.6c: Distinguish between continuous and discrete variation, using examples.
- 20N.2.HL.TZ0.5b: Using a Punnett square, determine how a smooth-haired puppy could be produced in the offspring.
- 20N.2.HL.TZ0.5a: Identify the genotype of the male wire-haired dog.
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20N.2.HL.TZ0.8b:
Describe the changes that occur in gene pools during speciation.
- 17N.1.HL.TZ0.36: In a plant, dark leaves are dominant to pale leaves and yellow seeds are dominant to white...
- 17M.1.HL.TZ2.19: The genetic determination of dogs’ coats can be quite complex, with many different genes...
- 18M.1.HL.TZ2.17: Which process could cause non-disjunction if it occurred during meiosis? A. Sister...
- 17M.2.HL.TZ1.7b: Outline the process of speciation.
- 22M.2.HL.TZ2.3a: State the alternative hypothesis for this study.
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22M.1.HL.TZ2.36:
Three-spined stickleback fish (Gasterosteus aculeatus) vary in the number of armour plates. The graph shows the frequency of individuals with low, partial or complete plating in a three-spined stickleback population living in Kennedy Lake, Vancouver Island, Canada.
[Source: Reprinted from Current Biology, 24, Marchinko, K.B., Matthews, B., Arnegard, M.E., Rogers, S.M. and Schluter, D., Maintenance of a Genetic Polymorphism with Disruptive Natural Selection in Stickleback.
2014. pp.1289–1292 with permission from Elsevier.]Which type of natural selection could result in this pattern of variation in the population?
A. Disruptive
B. Directional
C. Stabilizing
D. Convergent
- 17M.2.HL.TZ1.7a: Discuss the role of genes and chromosomes in determining individual and shared character...
- 19M.2.HL.TZ1.2d.ii: The offspring, which were all heterozygous for grey body and normal wings, were crossed with...
- 19M.2.HL.TZ1.7b: Explain how natural selection can lead to speciation.
- 17M.3.HL.TZ2.1c: Explain the concept of directional selection with respect to this example.
- 21M.1.HL.TZ2.36: Which cell is a polyploid zygote produced by fusion of one haploid and one diploid gamete?
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22M.2.HL.TZ2.3d:
When the data in the table were used to calculate chi-squared, the calculated value was 0.056. The critical value is 3.84. Explain the conclusion that can be drawn from the calculated and critical values for chi-squared.