Date | May 2015 | Marks available | 2 | Reference code | 15M.1.hl.TZ2.9 |
Level | HL only | Paper | 1 | Time zone | TZ2 |
Command term | State | Question number | 9 | Adapted from | N/A |
Question
State the set of values of a for which the function x↦logax exists, for all x∈R+.
[2]
a.
Given that logxy=4logyx, find all the possible expressions of y as a function of x.
[6]
b.
Markscheme
a>0 A1
a≠0 A1
[2 marks]
a.
METHOD 1
logxy=lnylnx and logyx=lnxlny M1A1
Note: Use of any base is permissible here, not just “e”.
(lnylnx)2=4 A1
lny=±2lnx A1
y=x2or1x2 A1A1
METHOD 2
logyx=logxxlogxy=1logxy M1A1
(logxy)2=4 A1
logxy=±2 A1
y=x2ory=1x2 A1A1
Note: The final two A marks are independent of the one coming before.
[6 marks]
Total [8 marks]
b.
Examiners report
[N/A]
a.
[N/A]
b.