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Date None Specimen Marks available 6 Reference code SPNone.2.hl.TZ0.13
Level HL only Paper 2 Time zone TZ0
Command term Find Question number 13 Adapted from N/A

Question

The function f is defined on the domain [0, 2] by \(f(x) = \ln (x + 1)\sin (\pi x)\) .

Obtain an expression for \(f'(x)\) .

[3]
a.

Sketch the graphs of f and \(f'\) on the same axes, showing clearly all x-intercepts.

[4]
b.

Find the x-coordinates of the two points of inflexion on the graph of f .

[2]
c.

Find the equation of the normal to the graph of f where x = 0.75 , giving your answer in the form y = mx + c .

[3]
d.

Consider the points \({\text{A}}\left( {a{\text{ }},{\text{ }}f(a)} \right)\) , \({\text{B}}\left( {b{\text{ }},{\text{ }}f(b)} \right)\) and \({\text{C}}\left( {c{\text{ }},{\text{ }}f(c)} \right)\) where a , b and c \((a < b < c)\) are the solutions of the equation \(f(x) = f'(x)\) . Find the area of the triangle ABC.

[6]
e.

Markscheme

\(f'(x) = \frac{1}{{x + 1}}\sin (\pi x) + \pi \ln (x + 1)\cos (\pi x)\)     M1A1A1

[3 marks]

a.

     A4

Note: Award A1A1 for graphs, A1A1 for intercepts.

 

[4 marks]

b.

0.310, 1.12     A1A1

[2 marks]

c.

\(f'(0.75) = - 0.839092\)     A1

so equation of normal is \(y - 0.39570812 = \frac{1}{{0.839092}}(x - 0.75)\)     M1

\(y = 1.19x - 0.498\)     A1

[3 marks]

d.

\({\text{A}}(0,{\text{ }}0)\)

\({\text{B(}}\overbrace {0.548 \ldots }^c,\overbrace {0.432 \ldots }^d)\)     A1

\({\text{C(}}\overbrace {1.44 \ldots }^e,\overbrace { - 0.881 \ldots }^f)\)     A1

Note: Accept coordinates for B and C rounded to 3 significant figures.

 

area \(\Delta {\text{ABC}} = \frac{1}{2}|\)(ci + dj) \( \times \) (ei + fj)\(|\)     M1A1

\( = \frac{1}{2}(de - cf)\)     A1

\( = 0.554\)     A1

[6 marks]

e.

Examiners report

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Syllabus sections

Topic 4 - Core: Vectors » 4.5 » The definition of the vector product of two vectors.

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