Date | May 2007 | Marks available | 8 | Reference code | 07M.2.hl.TZ0.2 |
Level | HL only | Paper | 2 | Time zone | TZ0 |
Command term | Find | Question number | 2 | Adapted from | N/A |
Question
An automatic machine is used to fill bottles of water. The amount delivered, \(Y\) ml , may be assumed to be normally distributed with mean \(\mu \) ml and standard deviation \(8\) ml . Initially, the machine is adjusted so that the value of \(\mu \) is \(500\). In order to check that the value of \(\mu \) remains equal to \(500\), a random sample of 10 bottles is selected at regular intervals, and the mean amount of water, \(\overline y \) , in these bottles is calculated. The following hypotheses are set up.
\({{\rm{H}}_0}:\mu = 500\) ; \({{\rm{H}}_1}:\mu \ne 500\)
The critical region is defined to be \(\left( {\overline y < 495} \right) \cup \left( {\overline y > 505} \right)\) .
(i) Find the significance level of this procedure.
(ii) Some time later, the actual value of \(\mu \) is \(503\). Find the probability of a Type II error.
Markscheme
(i) Under \({{\rm{H}}_0}\) , the distribution of \({\overline y }\) is N(500, 6.4) . (A1)
Significance level \( = {\rm{P}}\overline y < 495\) or \( > 505|{{\rm{H}}_0}\) M2
\( = 2 \times 0.02405\) (A1)
\( = 0.0481\) A1 N5
Note: Using tables, answer is \(0.0478\).
(ii) The distribution of \(\overline y \) is now N(\(503\), \(6.4\)) . (A1)
P(Type ΙΙ error) \( = {\rm{P}}(495 < \overline y < 505)\) (M1)
\( = 0.785\) A1 N3
Note: Using tables, answer is \(0.784\).
[8 marks]