| Date | May 2009 | Marks available | 1 | Reference code | 09M.1.sl.TZ2.3 |
| Level | SL only | Paper | 1 | Time zone | TZ2 |
| Command term | State | Question number | 3 | Adapted from | N/A |
Question
The following table shows the number of errors per page in a 100 page document.
State whether the data is discrete, continuous or neither.
Find the mean number of errors per page.
Find the median number of errors per page.
Write down the mode.
Markscheme
Discrete (A1) (C1)
[1 mark]
\(\frac{{0 + 24 + 40 + 51 + 44}}{{100}} = \frac{{159}}{{100}} = 1.59\) (M1)(A1) (C2)
Notes: Award (M1) for correctly substituted formula.
Award (M1)(A1) for 1 or 2 if 1.59 is seen.
Award (M0)(A0) for 1 or 2 seen with no working.
[2 marks]
1 (M1)(A1) (C2)
Note: Award (M1) for attempt to order raw data (if frequency table not used) or (M1) for indicating halfway between 50th and 51st result or (M1) for 50th percentile seen.
[2 marks]
0 (A1) (C1)
[1 mark]
Examiners report
This question was not well answered by a number of candidates. In this part, many did not know that the data was discrete.
This question was not well answered by a number of candidates. The most common error in this part was (0 + 1 + 2 + 3 + 4) / 5 = 2.
This question was not well answered by a number of candidates.
This question was not well answered by a number of candidates.
Many candidates did not know how to find the median and the most common incorrect answer for this part was 11.
