Calculate the distance travelled by the Earth in one day.

Give your answer to part (a) in the form \(a \times {10^k}\) where \(1 \leqslant a \leqslant 10\) and \(k \in \mathbb{Z}\) .

\(2\pi \frac{{150000000}}{{365}}\)     (M1)(A1)(M1)

Notes: Award (M1) for substitution in correct formula for circumference of circle.

Award (A1) for correct substitution.

Award (M1) for dividing their perimeter by \(365\).

Award (M0)(A0)(M1) for \(\frac{{150000000}}{{365}}\) .

\(2580000{\text{ km}}\)     (A1)     (C4)

[4 marks]

\(2.58 \times {10^6}\)     (A1)(ft)(A1)(ft)     (C2)

Notes: Award (A1)(ft) for \(2.58\), (A1)(ft) for \({10^6}\) . Follow through from their answer to part (a). The follow through for the index should be dependent not only on the answer to part (a), but also on the value of their mantissa. No (AP) penalty for first (A1) provided their value is to 3 sf or is all their digits from part (a).

[2 marks]

A significant number of candidates simply divided \(150 000 000\) by \(365\) and consequently lost all but one method mark in part (a). Presumably these candidates assumed that the given value was the circumference rather than the radius.

A significant number of candidates simply divided \(150 000 000\) by \(365\) and consequently lost all but one method mark in part (a). Presumably these candidates assumed that the given value was the circumference rather than the radius. Recovery in part (b) did, however, result in many getting both marks here. It was noted on some answers to part (b) that the index power was negative rather than positive suggesting a misunderstanding by candidates of standard form.