Date | November 2014 | Marks available | 3 | Reference code | 14N.1.sl.TZ0.15 |
Level | SL only | Paper | 1 | Time zone | TZ0 |
Command term | Find | Question number | 15 | Adapted from | N/A |
Question
Consider the curve y=x2+ax−1, x≠0.
Find dydx.
The gradient of the tangent to the curve is −14 when x=1.
Find the value of a.
Markscheme
2x−ax2 (A1)(A1)(A1) (C3)
Notes: Award (A1) for 2x, (A1) for −a and (A1) for x−2.
Award at most (A1)(A1)(A0) if extra terms are present.
2(1)−a12=−14 (M1)(M1)
Note: Award (M1) for substituting 1 into their gradient function, (M1) for equating their gradient function to −14.
Award (M0)(M0)(A0) if the original function is used instead of the gradient function.
a=16 (A1)(ft) (C3)
Note: Follow through from their gradient function from part (a).