Date | November 2016 | Marks available | 7 | Reference code | 16N.1.sl.TZ0.7 |
Level | SL only | Paper | 1 | Time zone | TZ0 |
Command term | Find | Question number | 7 | Adapted from | N/A |
Question
Let f(x)=m−1x, for x≠0. The line y=x−m intersects the graph of f in two distinct points. Find the possible values of m.
Markscheme
valid approach (M1)
egf=y, m−1x=x−m
correct working to eliminate denominator (A1)
egmx−1=x(x−m), mx−1=x2−mx
correct quadratic equal to zero A1
egx2−2mx+1=0
correct reasoning R1
egfor two solutions, b2−4ac>0
correct substitution into the discriminant formula (A1)
eg(−2m)2−4
correct working (A1)
eg4m2>4, m2=1, sketch of positive parabola on the x-axis
correct interval A1 N4
eg|m|>1, m<−1 or m>1
[7 marks]
Examiners report
[N/A]